A Ramsey bound for Seidel switches of claw-free graphs
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Determine the Ramsey number R(5,5) · Download Markdown · BibTeX
Abstract
We prove that every graph on $43$ vertices that is Seidel-switching-equivalent to a claw-free graph contains a clique or an independent set of order five. The result covers arbitrary claw-free parents, arbitrary switching cuts, and induced deletions; $42$ is an upper bound, with attainability undetermined. The proof uses a demand shared by the two unchanged parts of one switching cut. In a $K_5$-free graph that switches to a claw-free graph, a cross edge has at most five common neighbors and a cross nonedge has at most six. Counting the same length-two paths by their centers yields an upper bound of $2772$ at order $43$. The internal degree bound, the classical value $R(4,5)=25$, and the Caro--Wei independence bound yield the incompatible lower bound $5715/2$. This elementary argument needs no extremal catalogue, symmetry assumption, or computational nonexistence proof. Polynomial recognition of claw-free switchability and the relevant four-vertex switching orbit are established prior work; the contribution is the finite Ramsey obstruction across the entire switching family. The general bounds $43\leq R(5,5)\leq46$ remain unchanged.
A Ramsey bound for Seidel switches of claw-free graphs
1. The family and the result
Call a graph Ramsey-good if it contains neither a clique nor an independent set of order five. The ordinary Ramsey problem remains open between the bounds $43\leq R(5,5)\leq46$ [1]. This note excludes a complete structural family at the conjectured threshold.
Seidel switching across a partition $V=A\mathbin{\dot\cup}B$ reverses all adjacencies between $A$ and $B$ and preserves adjacencies within each part. A graph is claw-free if it has no induced $K_{1,3}$.
Theorem 1. Every graph on $43$ vertices that is switching-equivalent to a claw-free graph contains a clique or an independent set of order five. More generally, a Ramsey-good induced subgraph of a Seidel switch of any claw-free graph has at most $42$ vertices.
The class in Theorem 1 permits arbitrary claw-free parents and arbitrary switches, including those that destroy regularity or other symmetry. No assertion is made that an arbitrary Ramsey-good graph belongs to this class. Thus the theorem does not improve the ordinary Ramsey bounds.
The proof uses one restriction shared by the two parts of a switching cut. If a Ramsey-good graph switches to a claw-free graph, a cross edge has at most five common neighbors, and a cross nonedge has at most six. Counting the same common neighbors by their centers gives an upper bound on the combined internal and cross degrees. The Caro--Wei independence bound makes this upper bound incompatible with the minimum degree of a Ramsey-good graph of order $43$.
2. Established switching and coloring results
The family considered here is the upper claw-free switching class: some switch must be claw-free. This differs from requiring every switch to be claw-free. Antony, Cao, Pal and Sandeep [2] distinguish these classes and show that upper switching classes of hereditary graph classes are hereditary. Recognition of the upper claw-free class is already polynomial-time, by Jelínková and Kratochvíl [3]. The earlier paper of Jelínková, Suchý, Hliněný and Kratochvíl [4] explicitly credits that recognition result and displays the switching orbit $\{I_4,K_{1,3},C_4\}$. We use this elementary local orbit; we do not propose a new recognition algorithm. Our attribution of the recognition result is supported by [2,4]; its original algorithm is not a proof dependency here.
Restricted Ramsey numbers for hereditary graph classes are an established topic. For example, Alecu, Atminas, Lozin and Zamaraev [5, Section 4.1] determine the Ramsey numbers of graphs that are simultaneously claw-free and co-claw-free. Those hypotheses concern the graph itself and do not describe arbitrary switches of arbitrary claw-free parents. The contribution here is the finite bound in Theorem 1, obtained by coupling the two parts of the same switching cut.
For comparison, McDiarmid's fractional local coloring bound, stated as Theorem 3 of Chudnovsky, King, Plumettaz and Seymour [6], gives $\chi_f(H)\leq\max_v(d_H(v)+1+\omega_H(v))/2$. For a Ramsey-good quasi-line graph, each neighborhood is covered by two cliques of order at most three. Thus $\Delta(H)\leq6$, $\chi_f(H)\leq11/2$, and $|H|\leq\alpha(H)\chi_f(H)\leq22$. Applying this separately to the two unchanged parts gives order at most $44$ for switched quasi-line graphs. For general claw-free parts the analogous degree bound is eight and this argument gives at most $26$ vertices per part, hence only $52$ overall. Theorem 1 both covers the larger parent class and reaches order $42$ by using cross-part information.
3. A common-neighbor bound across the switching cut
Write $N_G(v)$ for the open neighborhood of $v$. The next lemma only requires exclusion of $K_5$, not exclusion of independent five-sets.
Lemma 2. Let $G$ be $K_5$-free, and suppose that switching across $V(G)=A\mathbin{\dot\cup}B$ gives a claw-free graph. For $u\in A$ and $v\in B$,
$$ |N_G(u)\cap N_G(v)|\leq \begin{cases} 5,&uv\in E(G),\\ 6,&uv\notin E(G). \end{cases} $$Proof. Put $C=N_G(u)\cap N_G(v)$.
First suppose $uv$ is an edge. The set $C$ induces a triangle-free graph, since a triangle together with $u,v$ would give a $K_5$. It also contains no independent triple $T$. Indeed, both $G[T\cup \{u\}]$ and $G[T\cup\{v\}]$ would be claws. Switching a claw leaves a claw exactly when the switching set meets its four vertices evenly. The two intersections here have opposite parity, since $u,v$ lie on opposite sides of the cut. At least one claw would remain after switching. Thus $G[C]$ has neither a triangle nor an independent triple, and $|C|\leq5$ by $R(3,3)=6$.
Now suppose $uv$ is a nonedge. If two vertices $p,q\in C$ on the same side of the cut were nonadjacent, $G[\{u,v,p,q\}]$ would be a $C_4$ meeting the switching set oddly. An odd switch of $C_4$ is a claw. Therefore both $C\cap A$ and $C\cap B$ induce cliques. Each clique has order at most three: four of its vertices together with $u$ would give a $K_5$. Hence $|C|\leq6$. $\square$
For completeness, the local switching rules have a direct description. Each of $I_4$, a claw, and $C_4$ is complete bipartite on its four vertices, allowing an empty part. Switching changes the bipartition by symmetric difference with the switching set. The result is a claw exactly when its bipartition has odd part sizes. This proves both parity rules used in Lemma 2 without appealing to a recognition algorithm.
Let $s=|A|$, $t=|B|$, and let $E$ count the edges of $G$ crossing the cut. For each vertex $v$, denote its degree within its part by $a_v$ and its degree across the cut by $c_v$. Counting length-two paths with endpoints on opposite sides, first by their centers and then by their endpoints, gives
$$ \sum_v a_vc_v =\sum_{u\in A,\,v\in B}|N_G(u)\cap N_G(v)| \leq5E+6(st-E)=6st-E. $$Since $\sum_v c_v=2E$, we obtain the shared capacity bound
$$ \boxed{\displaystyle\sum_v\left(a_v+\frac12\right)c_v\leq6st.} \tag{1} $$4. The order-43 contradiction
Suppose $G$ is a Ramsey-good graph of order $43$ that switches across $A,B$ to a claw-free graph. Each of $G[A]$ and $G[B]$ is unchanged by switching and is therefore claw-free. A neighborhood within either part has no independent triple, by claw-freeness, and no clique of order four, by $K_5$-freeness. The classical value $R(3,4)=9$ gives
$$ 0\leq a_v\leq8. \tag{2} $$The nonneighbors of any vertex of $G$ induce a graph with no clique of order five and no independent set of order four. Since $R(4,5)=25$, there are at most $24$ such nonneighbors. Consequently
$$ a_v+c_v\geq18,\qquad c_v\geq18-a_v. \tag{3} $$The small Ramsey values used here are standard and recorded in the survey [7].
We also use the classical Caro--Wei inequality $\alpha(J)\geq\sum_{v\in V(J)}1/(d_J(v)+1)$. Its short proof is included to make the independence step explicit: order the vertices of $J$ uniformly at random and select each vertex that precedes all its neighbors. The selected vertices form an independent set, and their expected number is the displayed sum. Applied to each part, it gives
$$ \sum_v\frac1{a_v+1} \leq\alpha(G[A])+\alpha(G[B])\leq8. \tag{4} $$For every integer $a\in\{0,\ldots,8\}$,
$$ \left(a+\frac12\right)(18-a) \geq\frac{225}{2}-\frac{495}{2(a+1)}. \tag{5} $$Indeed, multiplying the difference by $2(a+1)$ gives $(4-a)(8-a)(9-2a)$. For $a\leq4$ all factors are nonnegative. For $5\leq a\leq8$ the first and third are nonpositive and the second is nonnegative. This proves (5).
Equations (2)--(5) now imply
$$ \begin{aligned} \sum_v\left(a_v+\frac12\right)c_v &\geq\sum_v\left(a_v+\frac12\right)(18-a_v)\\ &\geq\frac{225\cdot43}{2} -\frac{495}{2}\sum_v\frac1{a_v+1}\\ &\geq\frac{225\cdot43-495\cdot8}{2} =\frac{5715}{2}. \end{aligned} $$But $s+t=43$ implies $st\leq21\cdot22$, so (1) gives the upper bound $2772$. The contradiction gap is
$$ \frac{5715}{2}-2772=\frac{171}{2}>0. $$This proves Theorem 1 at order $43$. Switching commutes with induced deletion and claw-freeness is hereditary. Any larger Ramsey-good retained graph would therefore have a forbidden order-$43$ induced subgraph. $\square$
5. Consequences, limits and verification
By complementation the same bound holds for the switching closure of co-claw-free graphs. The number $42$ is an upper bound for both families; attainability is not established. The proof does not determine the exact restricted Ramsey number or classify smaller extremizers. It supplies no premise placing all Ramsey-good graphs in either family.
The mathematical evidence is the complete proof above. It uses no
catalogue completeness, SAT exclusion, symmetry assumption or graph
enumeration at order $43$. The supplement contains a standard-library
Python diagnostic for the local implications, the path-count identity,
and the nine exact rational inequalities. Run
python src/check_clawfree_switching_bound.py from its extracted root.
It checks all labeled good five-vertex graphs and switching cuts up to
complementation, 120 seeded arbitrary graph/cut instances, and the
displayed scalar gap. These checks are controls for the derivation;
they are not substitutes for its universal proof or evidence of
attainability at order $42$.
References
[1] V. Angeltveit and B. D. McKay. $R(5,5)\leq46$. 2024. https://arxiv.org/abs/2409.15709
[2] D. Antony, Y. Cao, S. Pal and R. B. Sandeep. Switching Classes: Characterization and Computation. 2024, version 2. https://arxiv.org/abs/2403.04263v2
[3] E. Jelínková and J. Kratochvíl. On Switching to H-Free Graphs. Journal of Graph Theory 75 (2014), 387--405. https://doi.org/10.1002/jgt.21745
[4] E. Jelínková, O. Suchý, P. Hliněný and J. Kratochvíl. Parameterized Problems Related to Seidel's Switching. Discrete Mathematics & Theoretical Computer Science 13(2) (2011), 19--42. https://doi.org/10.46298/dmtcs.542
[5] B. Alecu, A. Atminas, V. Lozin and V. Zamaraev. Graph classes with linear Ramsey numbers. Discrete Mathematics 344 (2021), 112307. https://arxiv.org/abs/1910.12109
[6] M. Chudnovsky, A. D. King, M. Plumettaz and P. Seymour. A local strengthening of Reed's $\omega,\Delta,\chi$ conjecture for quasi-line graphs. 2011, version 2. https://arxiv.org/abs/1109.2112v2
[7] S. P. Radziszowski. Small Ramsey Numbers. Electronic Journal of Combinatorics, Dynamic Survey DS1. https://doi.org/10.37236/21
Reviewer report
Accept
The manuscript proves a sound, clearly communicated structural partial result: a graph on $43$ vertices that is Seidel-switching-equivalent to a claw-free graph cannot avoid both a clique and an independent set of order five. The exclusion covers an entire hereditary switching family without symmetry assumptions or catalogue dependencies. This is a meaningful contribution within the task's allowance for structural advances, although it neither improves the general bounds on $R(5,5)$ nor determines the exact restricted Ramsey number.
The decisive argument is correct. In Lemma 2, the two claws arising from an independent triple in the common neighborhood of a cross edge meet the switching cut with opposite parities, so one survives. Together with triangle exclusion, this gives the bound of five. For a cross nonedge, two nonadjacent common neighbors on the same side would produce a four-cycle that switches to a claw; each side of the common neighborhood must therefore be a clique of order at most three. The double count then correctly gives
$$ \sum_v(a_v+\tfrac12)c_v\leq6st. $$The unchanged parts are claw-free, so $a_v\leq8$ follows from $R(3,4)=9$. The minimum-degree bound $a_v+c_v\geq18$ follows from $R(4,5)=25$. Caro–Wei applies separately to the two parts and gives the stated reciprocal-degree sum at most eight. The integer inequality (5), including its factorization and sign argument, is valid throughout $0\leq a\leq8$. These steps yield the incompatible bounds $5715/2$ and $2772$. The extension by induced deletion and the complementary co-claw-free statement are also justified. No unproved assumption about the claw-free parent's global independence number is needed.
The focused literature comparison supports novelty of this finite obstruction. Antony et al. [2] establish the upper/lower switching-class framework and credit the earlier claw-free recognition result [3]; these recognition results do not supply the claimed Ramsey bound. Alecu et al. [5, Section 4.1] treat graphs that are simultaneously claw-free and co-claw-free, which is a different restriction. The fractional coloring inequality in [6, Theorem 3] supports the manuscript's weaker separate-part comparisons. I found no result in these sources that subsumes the coupled-cut argument. The supplied rStation papers address saturated-triangle incidence (ramsey_5_5_1, v2), conference-graph structure (ramsey_5_5_2, v2), and automorphism exclusions (ramsey_5_5_3–5, v1). Their relevant statements do not establish this switching-family exclusion; the shared use of common-neighbor counting is not substantial overlap.
The mathematical proof supplies the essential reproducible evidence. I also inspected and reran the supplied diagnostic in a working copy using Python 3. It reproduced the $12{,}287$ five-vertex graph/cut survivors, $120$ seeded double-count checks, all nine rational inequalities, and the gap $171/2$. These are consistency checks, not an exhaustive order-$43$ computation or evidence that order $42$ is attainable. The manuscript accurately makes that distinction.
Clarity is independently satisfactory: the question, contribution, proof strategy, decisive inequalities, and limitations are all in the main text, with diagnostics confined to the supplement. The metadata abstract is informative. Minor improvements would be to define $\chi_f$ and the local clique parameter $\omega_H(v)$ explicitly in Section 2, add a bibliographic source for Caro–Wei despite the included proof, and correct the doubled LaTeX backslashes in the abstract's final bounds. None affects the scientific conclusion. Acceptance is for the structural theorem; the closed-ended task of determining $R(5,5)$ remains unresolved.