# Common images and saturation for second-center quadratic jets

Mira Cairn

## 1. The finite image behind a local index

The local arithmetic input to a quadratic interpolation determinant is
an index of polynomials with integral priced Hasse derivatives. A finite
algebra approximation retains the original source support, a scalar
denominator cap, and a cutoff in Taylor order [1]. The difficulty is
that the source image usually couples many target coefficients. Bounding
each coefficient separately can discard a leading amount of information.

We determine the entire image of the unrestricted ordinary polynomial
source in the first-digit algebra at the second approximate conjugate
center, for every prime. A polynomial source change decomposes that image
into explicit weighted Pascal blocks. We give two sufficient conditions
under which the original weighted finite source fills it. Consecutive
minors then give an explicit finite error and a closed piecewise cubic
image-volume formula. In the resulting stable source regimes, this is
an exact leading law for the original finite model, including every
linear scalar cap and positive derivative ratio allowed by the stated
conditions.

The result does not solve the weighted-source boundary for all caps.
Nevertheless, the unrestricted image gives an upper image capacity, hence
a lower index bound, for every finite source. On the fixed actual-node
contract used in [2], that bound improves a preceding elementary capacity
estimate, but remains below the known all-order index and the stronger
bound of [2]. We claim no new discriminant endpoint, census, or
classification. The contribution is an exact shared image and a proved
source comparison, rather than a new Smith algorithm or a numerical
extrapolation.

### Relation to earlier work

The closest prior result is [1, Sections 6–7]. It solves the full
first-center dyadic model for all source budgets by a source and target
change specific to that center. Here the center has degree $p^3$ and is
more accurate on quadratic nodes. Our decomposition works for every
prime, but first removes the source cutoff; bringing that cutoff back
requires the explicit saturation conditions below. Neither the stronger
center nor a target presentation alone would justify transferring the
earlier volume formula.

The all-order normal forms in [3,4] and their first-digit specialization
in [1, Section 8] provide one of our two saturation arguments. We reprove
the needed elementary specialization and do not claim it as a new
all-order result. The center translation and primitive support bounds in
[2] are different inputs: they give lower arithmetic witnesses on actual
quadratic nodes, without identifying the full capped coefficient image.

Regular bases, generalized factorials, and integer-valued divided
differences have a substantial classical theory; Bhargava [5] gives
explicit bases using generalized $P$-orderings. Our coefficient condition
is a specific bivariate weighted Hasse condition, and the theorem concerns
its ordinary-source image after a finite Taylor cutoff. We use elementary
monic division and consecutive Pascal determinants, proving the required
facts below. We do not introduce a new general theory of integer-valued
polynomials. Preliminary versions of the present construction were shared
in the public discussion [6]. The computations retain the modular Smith
implementation precedent credited in [7].

## 2. Definitions and main statements

Let $\mathcal O$ be an unramified discrete valuation ring of residue
characteristic $p$, with $v_p(p)=1$, and put $q=p^2$. All lengths are
$\mathcal O$-lengths. Define
$$
\mathcal A_1=\mathcal O[c,w]/(w^q-w-pc),\qquad
S_2=w^{p^3}-pc^p,
$$
$$
\mathcal B=\mathcal A_1[t,W]/(t^p-pW),\qquad z=S_2+t.
\tag{1}
$$
This is the first-digit coefficient algebra at the second center of [1].
Its normal basis is $w^ac^m t^bW^h$, with $a<q$, $b<p$ and $m,h\ge0$.
An ordinary Taylor coefficient of order $j=ph+b$ is multiplied by
$p^{\lfloor j/p\rfloor}$ in this basis.

For $J=ph+b$, $0\le b<p$, set
$$
\mathcal T_J=
\begin{cases}
(W^h),&b=0,\\
(t^bW^h,W^{h+1}),&b>0.
\end{cases}
\tag{2}
$$
It is exactly the span of normal Taylor orders at least $J$. In
particular, both generators in the second line are necessary. For
integers $d,J\ge1$ let $\mathcal Q_{d,J}=\mathcal B/(p^d,\mathcal T_J)$.

For integers $K,R\ge1$, put
$$
\Lambda_R=\{(r,s)\in\mathbb Z_{\ge0}^2:r+Ks<R\},\quad
C_R=\bigoplus_{(r,s)\in\Lambda_R}\mathcal O z^rw^s,\quad n_R=|\Lambda_R|.
$$
Denote its image in $\mathcal Q_{d,J}$ by $I_R(d,J)$, and define
$$
E_{K,R,J,d}=dn_R-\operatorname{length}I_R(d,J).
\tag{3}
$$
Equivalently, this is the index of
$p^{-d}[C_R\cap(p^d\mathcal B+\mathcal T_J)]$ above $C_R$.
Let $I_\infty(d,J)$ be the image of $\mathcal O[z,w]$ without a
source degree bound.

For $N\ge0$ and $0\le b<p$, define $M_N=\min(N,J-1)$ and the matrix
$$
B_{N,b}(j,r)=\binom rj
p^{pN+b-(p-1)r-j+\lfloor j/p\rfloor},
\quad 0\le j\le M_N,\quad 0\le r\le N.
\tag{4}
$$
The entry is zero when $j>r$. Let
$$
H=\min\left(pd-1,\ d+J-2-\left\lfloor\frac{J-1}{p}\right\rfloor\right).
\tag{5}
$$

**Theorem 1 (exact image and source saturation).** The image
$I_\infty(d,J)$ is the direct sum of the images of $B_{N,b}$ modulo
$p^d$, for $0\le N\le H$, $0\le b<p$, each with multiplicity $q$.
Moreover $I_R(d,J)=I_\infty(d,J)$ if either
$$
R>H+(p^3K-1)\min(J-1,H)+K(p^3-1),
\tag{6}
$$
or, when $K>p$,
$$
R\ge\max(K,p^3)(d-1)+p^3.
\tag{7}
$$
Neither condition is claimed necessary. In the usual chamber
$p<K\le p^3$, condition (7) is simply $R\ge p^3d$.

Define increasing marginal prices
$$
\mu_{N,b,i}=N+b-M_N+pi+\left\lfloor\frac{M_N-i}{p}\right\rfloor,
\quad 0\le i\le M_N,
$$
and the finite capacity
$$
\mathcal C_p(d,J)=q\sum_{N=0}^{H}\sum_{b=0}^{p-1}
\sum_{i=0}^{M_N}(d-\mu_{N,b,i})_+.
\tag{8}
$$
Here $x_+=\max(x,0)$.

**Theorem 2 (capacity and volume).** Write
$\ell_\infty(d,J)=\operatorname{length}I_\infty(d,J)$. Then
$$
0\le\mathcal C_p(d,J)-\ell_\infty(d,J)
\le 2p^3(H+1)\min(J,H+1)
\bigl(1+\lfloor\log_p\max(1,H)\rfloor\bigr).
\tag{9}
$$
Consequently, for every finite source,
$$
E_{K,R,J,d}\ge\max(0,dn_R-\mathcal C_p(d,J)).
\tag{10}
$$
If $d/R\to\eta>0$ and $J/R\to\varepsilon>0$, then
$$
\frac{\ell_\infty(d,J)}{R^3}\longrightarrow
\mathcal V_p(\eta,\varepsilon)
=\frac{p^3}{6}\left[
\eta^3-\frac{p}{p+1}(\eta-\varepsilon/p)_+^3
-\frac{1}{p+1}(\eta-p\varepsilon)_+^3\right].
\tag{11}
$$
For $J\ge pd$, there is also the exact finite formula
$$
\ell_\infty(d,J)=\mathcal C_p(d,J)=p^3\binom{d+2}{3}.
\tag{12}
$$

For clarity, put
$$
\gamma=\min\bigl(p\eta,\eta+(1-1/p)\varepsilon\bigr).
$$
If either
$$
\gamma+(p^3K-1)\min(\varepsilon,\gamma)<1,
\tag{13}
$$
or $K>p$ and $\max(K,p^3)\eta<1$, Theorem 1 gives the exact leading
finite-source index
$$
\frac{E_{K,R,J,d}}{R^3}\longrightarrow
\frac{\eta}{2K}-\mathcal V_p(\eta,\varepsilon).
\tag{14}
$$
Without these source conditions the right side, truncated below at zero,
is a lower limit bound, not an equality assertion. In the branch
$\varepsilon\le p\eta$, condition (13) simplifies to
$\eta+(p^3K-1/p)\varepsilon<1$.

## 3. Polynomial source coordinates and exact blocks

Set
$$
\begin{aligned}
A&=w^q-w=pc,\qquad u=p^{p-1}-1,\\
L(w)&=w^p+\sum_{i=1}^{p-1}\binom pi w^{p-i}(w^q-w)^i,\\
V&=z-L(w)=puc^p+t,\\
G&=p^{p-1}V-uA^p=p^{p-1}t.
\end{aligned}
\tag{15}
$$
These are exact polynomial identities, and $u$ is a unit. Indeed,
$w^{p^3}=(w+pc)^p$ in $\mathcal A_1$. Its first $p$ terms give $L$;
its last term, after subtracting $pc^p$, is $puc^p$.
Also $\deg_w L=p^3-p^2+1<p^3$.

The source algebra $\mathcal O[z,w]=\mathcal O[V,w]$ is free over
$\mathcal O[V,G]$ with basis
$$
w^aA^b,\qquad 0\le a<q,\quad0\le b<p.
\tag{16}
$$
To see this, $G=p^{p-1}V-u(w^q-w)^p$ is a polynomial in $w$ of
degree $p^3$ with unit leading coefficient. Monic division gives the
basis $1,w,\ldots,w^{p^3-1}$. Replacing $w^{a+qb}$ by $w^aA^b$
is an integral triangular change with unit diagonal.

Group the columns $w^aA^bV^rG^l$ by $N=r+l$. Their target terms have
$$
\deg_c+p\cdot\text{Taylor order}=pN+b.
\tag{17}
$$
The target coordinates for different triples $(a,b,N)$ are disjoint.
Within a fixed $N$, replacing $G$ by $A^p$ in the pair $(V,G)$ is
an invertible integral linear change, because $u$ is a unit. Its degree
$N$ symmetric power is also integral and invertible. We may therefore
use the columns $w^aA^{p(N-r)+b}V^r$, $0\le r\le N$.

Expanding $V=puc^p+t$, its order-$j$ term is
$$
\binom rj u^{r-j}p^{pN+b-(p-1)r-j+\lfloor j/p\rfloor}
w^ac^{p(N-j)+b}t^{j\bmod p}W^{\lfloor j/p\rfloor}.
$$
Separate unit rescalings of rows and columns remove $u^{r-j}$, giving
(4). This proves the exact direct-sum statement before truncating $N$.
For $N<J$, the smallest scalar entry price is
$b+\lfloor N/p\rfloor$; for $N\ge J$ it is
$N+b-J+1+\lfloor(J-1)/p\rfloor$. Thus every block above (5) vanishes
modulo $p^d$. No binomial coefficient has been assumed to be a unit.

For example, when $p=2$,
$$
V=z+w^2-2w^5=2c^2+t,\qquad G=2V-A^2=2t.
$$
This polynomial source change is distinct from replacing a target by
its leading homogeneous terms. Every coefficient of the actual center
has been retained.

## 4. Bringing back the finite source

### A complete-prefix argument

Give $w$ degree one and $z,V,G$ degree $p^3$. The change $z\leftrightarrow V$
is filtered in both directions, since $\deg L<p^3$. The monic relation
for $w^{p^3}$ preserves this filtration. Consequently the complete prefix
$$
w^aA^bV^rG^l,\quad a<q,\quad b<p,\quad r+l\le H,
$$
is also spanned by
$$
w^kz^rG^l,\quad k<p^3,\quad r+l\le H.
\tag{18}
$$
Both are bases for the filtered piece of degree less than $p^3(H+1)$.
This uses a complete prefix; it does not identify an arbitrary weighted
partial boundary with a rectangle.

The image of a column with $l\ge J$ vanishes, by $G=p^{p-1}t$.
Every remaining column in (18) has original source weight at most
$$
r+Kk+p^3Kl
\le H+(p^3K-1)\min(J-1,H)+K(p^3-1).
$$
Condition (6) puts all these columns in $C_R$. They span the unrestricted
image, proving the first sufficient condition.

### An all-order cap argument

We record the relevant specialization of [1, Section 8]. Put
$$
A_0=(z^p-w)/p,\qquad V_0=(z^{p^3}-z^p)/p.
$$
For the first center $S_1=w^p$, its all-order priced algebra is
$$
\mathcal B_1=\mathcal O[z,A_0,V_0],\qquad
z^{p^3}-z^p=pV_0.
\tag{19}
$$
Here is a direct check. Expanding $z=w^p+t$ shows that $A_0$ belongs
to $\mathcal B_1$, using $w^q-w=pc$ and $t^p=pW$. Substitution
$w=z^p-pA_0$ in $c=(w^q-w)/p$ then shows that $V_0$ belongs to it.
Conversely this substitution expresses $c$ integrally in $z,A_0,V_0$.
Furthermore
$t=z-(z^p-pA_0)^p=z-z^q+p^2H_0(z,A_0)$ for an integral polynomial
$H_0$. Its $p$th power divided by $p$ is integral in (19): all mixed
terms are integral, and $(z-z^q)^p/p$ is integral by the relation in
(19), including $p=2$. This proves both inclusions. Monic division gives
the target basis $z^eA_0^sV_0^n$, $e<p^3$.

Now $S_2-S_1\in p\mathcal A_1$. Translation of $t$ by an element
of $p\mathcal A_1$ preserves $\mathcal A_1[t,t^p/p]$ in both
directions. Thus the all-order algebras at the two centers agree.
Their finite Taylor cutoffs need not agree.

When $K>p$, the ordinary source has the integral triangular basis
$$
z^e(z^p-w)^s(z^{p^3}-z^p)^n,
\quad e<p^3,\quad e+Ks+p^3n<R.
\tag{20}
$$
The leading ordinary monomials are distinct; replacing a $w$ by $z^p$
lowers original weight, and replacing $z^{p^3}$ by $z^p$ also lowers it.
The normal images of (20) are exactly $p^{s+n}z^eA_0^sV_0^n$.
Only $s+n<d$ survives cap $d$. All such unrestricted columns lie in
$C_R$ under (7), since
$$
e+Ks+p^3n\le p^3-1+\max(K,p^3)(d-1).
$$
Filling the all-order image fills every finite Taylor projection. This
proves the second sufficient condition in Theorem 1.

The same proof gives the complete all-order capped spectrum
$$
\min\left(d,s+\left\lfloor\frac r{p^3}\right\rfloor\right),
\qquad r+Ks<R,\quad K>p.
\tag{21}
$$
It also applies at finite $J\ge pd$, because every ordinary source
Taylor coefficient of order at least $pd$ has its explicit price
divisible by $p^d$.

## 5. Every-minor bounds and a closed volume

For a $k$-minor of (4), the scalar column prices decrease with $r$ and
the row prices decrease with $j$. Their minimum uses the largest $k$
rows and columns and equals $\sum_{i=0}^{k-1}\mu_{N,b,i}$. The
remaining binomial determinant is integral. Expanding minors after
adjoining the scalar cap, or using invariant factors over a DVR, gives
$$
\operatorname{length}(\operatorname{im}B_{N,b}\bmod p^d)
\le\sum_{i=0}^{M_N}(d-\mu_{N,b,i})_+.
\tag{22}
$$
The prices increase with $i$, so taking all positive marginals gives
the maximum rank contribution.

For the reverse estimate select consecutive row and column indices
ending at $M=M_N$ and $N$. Their binomial determinant is
$$
\prod_{i=0}^{k-1}
\frac{(N-k+1+i)!\,i!}
{(M-k+1+i)!\,(N-M+i)!}.
\tag{23}
$$
Factoring the initial binomial coefficients reduces the remaining
determinant to the Vandermonde determinant of consecutive integers,
which proves (23). Legendre's factorial formula cancels its linear
terms. The two positive base-$p$ digit sums in each factor show that
its valuation is at most
$2k(1+\lfloor\log_p\max(1,N)\rfloor)$. This is the same classical
consecutive-minor estimate used in [1, Section 6]. Choose the rank
maximizing the right side of (22), and sum this error over all blocks.
There are at most $p^3(H+1)$ blocks with multiplicity, each of rank at
most $\min(J,H+1)$, proving (9).

The finite capacity is not generally an exact image length. At
$p=2,N=2,b=0,J=2,d=2$, the block has capped invariant exponents
$(2,2)$ and zero image length. Its marginal prices from (8) are
$(1,3)$, giving capacity one. This example prevents replacing a bound
on the binomial determinant by equality.

For the limit, bounded residue terms $b$ and floors change the capacity
by $O_{p,\eta,\varepsilon}(R^2)$ for bounded integer rounding. In
$N<J$, put $i/R=x$ and $(N-i)/R=y$. The limiting price is $px+y/p$
on the triangle $x,y\ge0$, $x+y<\varepsilon$. In $N\ge J$, summing
the remaining ray gives
$$
\frac{\mathcal V_p}{p^3}=
\int_{\substack{x,y\ge0\\x+y<\varepsilon}}
(\eta-px-y/p)_+\,dx\,dy
+\frac12\int_0^\varepsilon
\bigl(\eta-\varepsilon/p-(p-1/p)x\bigr)_+^2\,dx.
\tag{24}
$$
For an explicit evaluation, write
$a=\eta-\varepsilon/p$ and $b=p-1/p$. Integrating first in $y$
shows that the first integral in (24) is
$$
\frac16\left[
\eta^3-(\eta-p\varepsilon)_+^3
-\frac p b\bigl(a_+^3-(a-b\varepsilon)_+^3\bigr)\right].
$$
The second is
$(a_+^3-(a-b\varepsilon)_+^3)/(6b)$.
Since $a-b\varepsilon=\eta-p\varepsilon$, their sum is exactly
(11). The two changes of formula occur at
$\varepsilon=\eta/p$ and $\varepsilon=p\eta$.

If $J\ge pd$, all nonzero blocks have $M=N$. The determinant in
(23) is then one at every rank, so (22) is exact. The all-order
description also counts its length directly:
$$
p^3\sum_{s+n<d}(d-s-n)=p^3\binom{d+2}{3}.
$$
This proves (12). Finally $n_R=R^2/(2K)+O_K(R)$, yielding (14) under
either strict source condition.

![For primes 2 and 3, the exact unrestricted image volume rises with derivative ratio and levels off at its all-order capacity. The coefficientwise bound has the same initial slope but is larger away from zero.](supplement/figures/common-image-volume.png)

*Figure 1.* Image lengths divided by $p^3\eta^3/6$, as functions of
$\varepsilon/\eta$. Solid curves are (11); dashed curves are the
coefficientwise upper bound in Section 7. These are unrestricted image
capacities, not actual-node indices.

## 6. The value endpoint

For $J=1$, each block has one row. Its least valuation is $N+b$,
attained by $r=N$. Hence the unrestricted image has exact coefficient
price
$$
\left\lfloor\frac mp\right\rfloor+(m\bmod p)
\quad\text{at }w^ac^m,\quad a<q,
$$
and length
$$
\ell_\infty(d,1)=\frac q2\sum_{b=0}^{p-1}(d-b)_+((d-b)_++1).
\tag{25}
$$
For $p=2$ this is $4d^2$, and (6) reduces to $R\ge d+7K$.
Thus
$$
E_{K,R,1,d}=dn_R-4d^2\qquad(p=2,\ R\ge d+7K).
\tag{26}
$$
This endpoint also has a direct triangular proof. Write
$S_2=w^2+2c^2+4wc$. Giving $w,c,2$ weights $0,1,-2$ shows that
every source value has coefficient valuation at least $\lceil m/2\rceil$
at $w^ac^m$. Order normal rows by $a+4m$. The columns $S_2^rw^b$,
$b<8$, have leading row $8r+b$ and leading coefficient
$2^{r+\lfloor b/4\rfloor}$, exactly the required row price. Dividing
the rows by their prices makes the complete prefix through $8d-5$
integral triangular with unit diagonal. Its source weights are at most
$d-1+7K$. This verifies (26) without a Smith calculation. The price
$\lceil m/p\rceil$ would be incorrect for general $p$ in (25).

## 7. What the image capacity contributes to an actual contract

For comparison, a direct coefficient filtration gives the larger capacity
$$
\mathcal C_p^{\mathrm{coord}}(d,J)
=q\sum_{j=0}^{J-1}\left(v_j+\frac p2v_j(v_j-1)\right),
\qquad v_j=(d-\lfloor j/p\rfloor)_+.
\tag{27}
$$
Indeed, give $c,W$ weights $1,p$, give $w,t$ weight zero, and give
the scalar $p$ weight $-p$. The relations and $S_2$ preserve weight
at most zero. Every normal source coefficient at $w^ac^mt^bW^h$
has valuation at least $h+\lceil m/p\rceil$. Summing these separate
coordinate capacities gives (27). It ignores the common-image relations
retained by Theorem 1. Its leading volume is
$$
\frac{p^4}{6}\bigl[\eta^3-(\eta-\varepsilon/p)_+^3\bigr].
$$
At $p=2,K=3,\eta=1,\varepsilon=1/100$, the lower index coefficient
from (10) is $127263/1000000$, compared with $380599/3000000$ from
(27). This is a finite-model lower bound outside the saturation conditions.

To reach the actual quadratic conjugate graph, the second center is
accurate modulo $p^2$. The priced Taylor translation in [1, Section 3]
therefore requires an extra model budget $h$ with
$$
2(h+1)-\lceil(h+1)/p\rceil\ge d.
\tag{28}
$$
The resulting sufficient model lattice is contained in the actual
lattice. Its index gives an absolute lower bound; it is not additional
credit that can be added to another absolute index.

On the unchanged contract
$$
(p,K,R,J_0)=(3,17,28560,3769),\qquad n_R=24004680,
$$
we evaluated (10) at model budget $J_0+h$, for each scalar cap from zero
through $v_3((R-1)!)$. The maximum is $21315571092$, at $d=1332$ and
$h=799$. The analogous maximum from (27) is $12312403950$.
The published all-order actual index is $22912902086$, and [2] gives
$22963131739$. Both are larger. Moreover the maximizing model budget
$4568$ exceeds $pd=3996$, so this optimum is already in the capped
all-order regime of (12). It supplies no new finite-budget excess.

This comparison identifies the remaining issue: a sharper theorem must
retain the position of the weighted source inside the common image outside
the stable regimes, or use a more accurate center and coefficient algebra.
The formula for an unrestricted image alone does not resolve that issue.

## 8. Reproduction and limitations

The supplement supplies three exact suites. Five dyadic value-source
contracts check the coefficient prices, triangular spanning columns and
complete capped spectra. Five full Taylor-source contracts at $p=2,3$
compare original coefficient matrices directly with the blocks of
Theorem 1 under (6). Five further contracts check (7) and (21), including
finite budgets where the image differs from its all-order projection.
The source identities are also checked at $p=2,3,5,7,11$.

Separate rational polygon integrations verify (11) in 32 cases across its
three regimes. The finite capacity code is checked against literal sums
at four primes. It sums quadratic polynomials in residue classes in
$O(p^2)$ arithmetic operations per pair $(d,J)$, so the actual-contract
comparison uses no large Smith matrix. A saved contract outside (6)
rejects an unjustified extension of (26), and the block following (23)
rejects equality between capacity and exact finite image length.

Run `python verify.py` from the extracted supplement. Python 3.10 or later
and NumPy are required. The suites use at most five CPU processes, with
numerical-library threads set to one. All mathematical calculations use
integers or rational numbers. The NumPy modular elimination checks its
integer-overflow bound. Expected complete outputs, code provenance,
figure values and a manifest are supplied. Plotting is optional and uses
Matplotlib. These are author implementations and checks, not an independent
audit or a formal verification of the proofs.

The exact statements concern the first-digit coefficient model at $S_2$.
The leading law for the full weighted-source boundary, and the leading
finite-budget index on actual quadratic nodes, remain open here. No
classification theorem or class-number census is used or claimed.
AI assistance: OpenAI Codex (Mira Cairn). Text is CC BY 4.0 and new code
is MIT; the reused routine retains its implementation attribution.

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