# Mixed-residue subtraction for quadratic-twisted cubic two-mark forms

## 1. Contribution and statement

We work over the Eisenstein field $F=\mathbb Q(\omega)$, where
$\omega^2+\omega+1=0$, with ring $\mathcal O$ and ideal norm $N$.
Nonzero ideals prime to3 are represented by a fixed primary generator.
All cubic symbols, additive characters and Gauss sums use the compatible
primary convention of Brubaker--Bump--Friedberg--Hoffstein [1]. Finite
changes of this convention are kept as fixed ray components. Characters
are extended by zero at nonunits of their original moduli.

This paper estimates the cost of subtracting a particular mixed-pole
model from a signed, divisor-weighted correlation. The model comes from
the cubic $A_2$ Eisenstein coefficient with a moving quadratic twist in
both coefficient coordinates. The exceptional Levi and its Eulerian
Whittaker functional are established theory [2--5]. The contribution is
their application to the actual numerator-deleted, squarefree two-mark
source, followed by a weighted mean and a bound for both cross terms.

Let $\eta=\eta_\kappa$ run through a fixed quadratic Hecke ray family,
with squarefree good conductor $\kappa$, $N\kappa\asymp K$. We exclude
the principal global character. Components at2 and3 lie in a fixed finite
collection; at2 we allow the actual quadratic components, including wild
ones. There is no varying auxiliary ramified character. Write

$$
G(n,f)=G(f)\overline{\rho_f(n)},\qquad |G(f)|=1
\quad(f\text{ squarefree},\ (n,f)=1),                         \tag{1.1}
$$

where $G(f)$ is the normalized cubic Gauss sum and $\rho_f$ the cubic
character. Zeros are retained in (1.1). For fixed smooth functions
$W_1,W_2$ supported in compact subintervals of $(0,\infty)$, define

$$
F_{n,\eta}(L_1,L_2;D)=
\sum_{\substack{r,s\text{ squarefree}\(r,s)=1\(rs,nD)=1}}
\frac{\eta(rs)G(n,rs)}{\sqrt{N(rs)}}
 W_1(Nr/L_1)W_2(Ns/L_2).                                  \tag{1.2}
$$

Here $D$ is a common deletion ideal. Quadratic conductor zeros are
already present in $\eta(rs)$. There is no requirement $(n,\kappa)=1$.
Normalization by $(L_1L_2)^{-1/2}$ instead is equivalent after multiplying
the fixed profiles by powers of their arguments.

The finite construction in Section5 associates to (1.2) a mixed-pole
model $R_{n,\eta}$ and defines $C_{n,\eta}=F_{n,\eta}-R_{n,\eta}$.
It uses a finite collision inverse, followed by a convergent integral of
the generic residue on $s+w=4/3$. It does not assert that an infinite
squarefree projection is automorphic.

Choose two pairs of profiles, with
$L_1L_2=M_1M_2=Q$, and set

$$
w(u)=\sum_{ae=u}\mu(a)^2U(Na/D_0)V(Ne/E),\qquad
X=D_0E\asymp Q^2,                                         \tag{1.3}
$$

where $U,V$ are fixed smooth annular profiles, possibly complex valued.
For $A=F,R,C$, write

$$
A^+_{g_1,g_2;\kappa}(u)=
A_{gu,\eta_\kappa}(L_1/Ng_1,L_2/Ng_2;Dg),\qquad g_1g_2=g,
                                                               \tag{1.4}
$$

and define $A^-_{h_1,h_2;\kappa}$ with the second pair of profiles and
$M_1,M_2$, where $h_1h_2=g$. Every split is squarefree and coprime.
Only nonempty original daughter supports are included. Define

$$
\begin{aligned}
\mathcal S(A^+,A^-)=
\sum_{\kappa}\sum_{g\text{ squarefree}}
\frac{\mu(g)}{Ng}
\sum_{\substack{u\text{ primary}\(g,u\kappa)=1}}w(u)
\sum_{\substack{g_1g_2=g\h_1h_2=g}}
A^+_{g_1,g_2;\kappa}(u)
\overline{A^-_{h_1,h_2;\kappa}(u)} .                         \tag{1.5}
\end{aligned}
$$

Common additional deletions and fixed compatible ray phases may be
retained. A common Mellin integral of such forms is permitted when its
weight has enough decay to pay the finite smooth seminorms used below.
Profiles cannot be chosen independently for different arithmetic rows.

**Theorem 1.** For every $\epsilon>0$, in the setting (1.1)--(1.5),

$$
\left|\mathcal S(F^+,F^-)-\mathcal S(C^+,C^-)\right|
\ll_\epsilon (KXQND)^\epsilon
\left(K^{1/2}Q^{1/6}X^{2/3}+Q^{1/3}X^{1/3}\right).         \tag{1.6}
$$

The constant depends on the fixed field, the specified finite packet,
the supports and finitely many smooth seminorms. At $X\asymp Q^2$,
restoring an outside factor $D_0/Q$ gives

$$
\frac{D_0}{Q}
\left|\mathcal S(F^+,F^-)-\mathcal S(C^+,C^-)\right|
\ll_\epsilon (KXQND)^\epsilon D_0(1+\sqrt{KQ}).             \tag{1.7}
$$

This is a difference estimate, not a bound for $\mathcal S(C^+,C^-)$.
The two-factor row weight arises when the coupled cubic reflection in
[10, proof of Proposition8.1] groups the original outer variable with
its Poisson dual; a quadratic twist can be kept in the common column
coefficient. Theorem1 addresses the specified squarefree two-mark
coefficient at that stage. It does not assert a new theorem for every
overlap sector of an earlier transform.

As a scale comparison, at $Q=D_0^{15/8}$ and $K=D_0^k$, (1.7) has
exponent $31/16+k/2$. It fits a target $D_0^{151/48-k/2}$ for
$k<29/24$, with a fixed margin before subsidiary powers. This
comparison states the cost of this component only. The complementary
signed estimate remains unproved. There is no new paid cutoff,
zero-free region or resolution of the Riemann hypothesis.

## 2. Related work and the source to be estimated

Kazhdan--Patterson [2] construct the exceptional representations and
their global residues. Their 1985 correction [3] withdraws an assertion
that an unramified spherical vector has vanishing Jacquet coordinates
outside a preferred class. We use the corrected finite-$S$ normalization,
not that assertion. Banks--Bump--Lieman [4], especially Sections2--3,
study the parameter-minus-one cover of $GL_{n-1}$ inside the degree-$n$
cover of $GL_n$. Their induced Whittaker integral has a spherical factor
$L(ns,\chi)/L(n^2s,\chi^n)$ in the odd-degree case. For $n=3$, this is
the outer Euler factor appearing below. Banks [5] supplies the heredity
argument. These are imported mechanisms, not novelty claims.

McNamara [6] provides the rank-one coefficient integral and spherical
Weyl expansion used for the local computations. The global realization
and nonfactorization issues for general metaplectic Fourier coefficients
are discussed by Brubaker--Friedberg [7]. We use uniqueness only after
passing to the particular exceptional Levi; we do not assert that the
original minimal Eisenstein coefficient is Eulerian.

Brubaker--Bump [8] identify residues of cubic $A_3$ multiple Dirichlet
series with the Friedberg--Hoffstein--Lieman double series. Their residue
method and twisted multiplicativity are direct precedents. Our estimate
instead retains a moving quadratic character in both $A_2$ columns,
natural equal Fourier indices, both column deletions, finite squarefree
projection, an irregular divisor weight, and the full signed
cross-column projector. The standard quadratic large sieve [9] and the
natural-row cubic estimate [10, (8.3)] supply the positive mean inputs.

Earlier rStation results [11,12] estimate different rank-one residual
pairings: primitive sextic Type-I sums and partial cubic Poisson packets.
The local co-period in [13] concerns the same special cubic cover but
an ordinary $GL_2$ test representation and a different functional. None
of these statements gives the subtraction (1.6). Conversely, (1.6)
does not replace their conclusions or control their regular remainders.

Let $H(C_1,C_2;m_1,m_2)$ denote the unnormalized coefficients in
[1, Proposition1], and put $H_0=H/\sqrt{N(C_1C_2)}$. Our ambient series is

$$
Z_{n,\eta}(s,w;D)=
\sum_{\substack{C_1,C_2\text{ primary}\(C_1C_2,nD)=1}}
\frac{\eta(C_1C_2)H_0(C_1,C_2;n,n)}
{(NC_1)^s(NC_2)^w}.                                      \tag{2.1}
$$

Both coefficient indices are deleted at every prime of $nD$. This is
essential: on the coprime locus the numerator twist is a character,
whereas the unrestricted Fourier coefficient has additional prime-power
terms at primes dividing $n$ [1, Proposition3]. The series (2.1) has all
prime-power coefficient states; its squarefree two-mark projection is
(1.2). We first identify its mixed residue, then project by a finite
identity. Formal root completion factors are not additional independent
pole terms.

## 3. The classical source and the exceptional functional

### 3.1. Moving quadratic minor weight

Use the fixed principal congruence group $\Gamma(3\mathcal O)$ and the
cubic splitting of [1, Section1]. For an integral representative $\gamma$,
put

$$
C_1(\gamma)=\gamma_{33},\qquad
C_2(\gamma)=\gamma_{22}\gamma_{33}-\gamma_{23}\gamma_{32}.
                                                               \tag{3.1}
$$

Multiply its Eisenstein summand by $\eta(C_1C_2)$ and by the indicators
that both minors are units at primes of $nD$. Left upper-unipotent
operations and the right lower-unipotent operations used in [1] preserve
these minors. Consequently the proof of [1, Proposition1] unfolds with
exactly the same archimedean Jacquet integral and with (2.1) as arithmetic
coefficient. The weight pulls out of each finite exponential sum. For a
fixed modulus, a finite cusp decomposition also proves continuation:
the weight is constant on the appropriate deeper-congruence cosets.
This observation alone gives no conductor-uniform norm estimate.

We need the more precise tensor realization. At a good finite place,
let $K_p=SL_3(\mathcal O_p)$ and

$$
\Delta_1(k)=k_{31},\quad
\Delta_2(k)=k_{21}k_{32}-k_{22}k_{31},\quad
f_{\eta,p}(k)=\eta_p(\Delta_1(k)\Delta_2(k))v_{0,p},       \tag{3.2}
$$

zero unless both minors are units. The underlying unramified genuine
torus vector is $v_{0,p}$. If $b\in B(\mathcal O_p)$ has diagonal $t$,
the two minors acquire factors $t_3$ and $t_1^{-1}$. Thus (3.2) has
the covariance for the torus representation twisted by
$\lambda_\eta(t)=\eta(t_3/t_1)$. The principal version of (3.2) implements
the two-column deletion at good primes of $nD$ outside the conductor.

Choose

$$
w_0=\begin{pmatrix}0&0&1\\0&-1&0\\1&0&0\end{pmatrix}.
$$

The compact support of (3.2) is represented by $w_0N(\mathcal O_p)$;
in those coordinates its value is $v_{0,p}$. With
$\operatorname{vol}(\mathcal O_p)=1$, its Jacquet input is therefore
$v_{0,p}$ for every integral pair of additive indices. On an integral
$\gamma$, its right translate by $w_0$ has scalar value
$\eta(C_1(\gamma)C_2(\gamma))$, including the two zeros.
The classical Fourier coefficient in [1] is evaluated at $w_0n(x)g$;
this and the finite right translation restore the full-cell input (3.2).
Fixed changes of Weyl signs are carried in the fixed packet.

To verify the global evaluation scalar, realize the original genuine
automorphic torus datum as functions $v$ and write $\ell(v)=v(1)$.
Multiplication

$$
(T_\eta v)(t)=\lambda_\eta(t)v(t),\qquad
\ell(T_\eta v)=\ell(v)                                   \tag{3.3}
$$

is well-defined because the ordinary Hecke character is trivial on the
rational torus. It intertwines the original representation with its
ordinary twist. On restricted tensors it is the tensor product of the
local twists. In the scalar torus-sum realization of [2, II.1], rational
torus representatives have $\lambda_\eta=1$ in every summand, giving
the same identity. This does not assert that $\ell$ factors locally.

The fixed classical base is a finite tensor packet: over this PID,
rational flags have integral representatives; fixed congruence support
selects the fixed Borel/ray classes. In the basic level3 convention,
units lift the diagonal classes. At a larger fixed level retain the
finitely many remaining diagonal classes. Twisting this fixed packet
by (3.3) and inserting (3.2) multiplies each scalar summand by exactly
the required minor weight. Hence no coefficient or packet multiplicity
depending on $\kappa$ is introduced. The same reasoning applies to the
principal deletion vectors at primes of $nD$.

### 3.2. The mixed residue in its actual Levi

Put $a=w-1/2$, $b=s-1/2$. The normalized torus exponent is

$$
\lambda=((2a+b)/3,(-a+b)/3,(-a-2b)/3).
$$

After the first simple reflection, the second root has exponent
$c=a+b$ and the ordinary character is $\eta(t_1)$. For the Levi

$$
\iota(m)=\operatorname{diag}(\det(m)^{-1},m),
                                                               \tag{3.4}
$$

this character is $\eta(\det m)$. Restricting the standard cubic torus
cocycle gives, for diagonal $m=(u,v)$ and $m'=(u',v')$,

$$
\sigma_3(\iota(m),\iota(m'))
=(u,v')_3(uv,u'v')_3^{-1}.                                \tag{3.5}
$$

Thus the Levi cover has KP parameter $-1\equiv2\pmod3$.
At $c=1/3$, its exceptional representation has a unique Whittaker model
by [2, Corollary I.3.6 and II.2.5--II.2.6]; the complex place is split.
The determinant twist preserves that property. It also commutes with
the global Levi residue: it is trivial on rational points and on the
unipotents used in the Whittaker integral.

The induced $SL_3$ model has the same Whittaker dimension by the
open-cell heredity proof [5]. Nonopen parabolic cells have a simple
root subgroup on which the section is invariant and the generic
character is nontrivial; their twisted Jacquet quotients vanish.
The open quotient is the Levi quotient. This argument uses the
unipotent splittings and the actual Levi (3.4).

There is no conflict with the nine ordinary Whittaker functionals in
[4, Section3]. Their $GL_3$ representation is induced from
$P_3=\{p\in P:\det p\in F_p^{*3}\}$. Its restriction to $SL_3$ splits
by $P_3\backslash GL_3/SL_3=F_p^*/F_p^{*3}$. The identity component is
induction from $P\cap SL_3$ of precisely the special $GL_2$ theta datum.
At tame places the quotient has nine classes. The displayed integral
in [4, (3.1)] lies in the determinant-one component; its degree-three
Weyl representative is a three-cycle. We use uniqueness in that
component, not uniqueness for all ordinary functionals on their $GL_3$
representation.

### 3.3. Normalization of the global functional

Normalize the good-place Levi residual map by its spherical scalar
$1+q^{-1}$. In the reflected principal series its spherical Jacquet
vector is $(1,q^{-1}u^{-1}G_0(2),0)$, where $u^3=q^{-1}$.
The Levi functional is the zeroth coordinate, so its spherical value
is1. Induction in stages identifies a section $f$ with

$$
F_f(g)(m)=\delta_P(m)^{-1/2}f(mg).
$$

The induced Whittaker integral integrates the Levi functional over the
two outer root coordinates. Substituting the Levi Jacquet integral
gives the full three-root Jacquet integral; the root-coordinate change
is triangular with determinant1. Hence its value is the zeroth
coordinate of the full outgoing Jacquet vector. This identity is first
proved on compact open-cell sections, then in a convergence chamber,
then meromorphically. It introduces no parameter-dependent scalar.

The global theta Whittaker functional is a fixed scalar times these
local normalized functionals on restricted tensors. In the corrected
KP construction the finite-$S$ formula contains

$$
T_2(S)^{-1},\qquad T_2(S)=\prod_{v\in S,\ v<\infty}(1+q_v^{-1}).
                                                               \tag{3.6}
$$

We retain this stabilization when making the local spherical values1.
It neither sets the unnormalized global scalar to1 nor supplies an
extra Euler factor. The determinant twist is1 on the Levi unipotents,
so the fixed scalar is unchanged as $\eta$ varies. The central unitary
parabolic twist is likewise1 there. Unfolding the outer nondegenerate
Fourier coefficient leaves the open cell even though theta is
noncuspidal: the nonopen cells are killed by the generic character.
Its constant term can have several Weyl contributions; those are not
separate alternative Fourier functional equations.

It follows that the residue of (2.1) uses the normalized scalar
functionals just specified, applied to each member of the fixed packet.
The remaining moving factors are computed next.

## 4. Residual density at every natural numerator

### 4.1. Local coefficient calculation

At a good prime of norm $q$, the cubic $SL_3$ torus lattice quotient
has three classes. Choose basis $E_t$, $t\in\mathbb Z/3$, so that
$\varpi^{r\alpha_1+s\alpha_2}v_0=x_1^rx_2^sE_{r+s}$.
For integral additive valuation $e$, put $h=e+1$. With unit additive
part $v$ define the unnormalized finite Gauss sums

$$
G_\varepsilon(k;v)=
\sum_{z\in\mathbb F_q^*}\overline\eta(z)^\varepsilon
\theta(z)^k\overline\psi(-vz),
                                                               \tag{4.1}
$$

where $\overline\eta$ is the tame quadratic character and $\theta$
the cubic character. Here $G_0(0;v)=-1$ and the other relevant sums
have modulus $q^{1/2}$. The raw simple-root coefficient is

$$
C_\varepsilon(x,e)E_t=
1_{\varepsilon=0}\frac{(1-q^{-1})x^{r(t)}}{1-x^3}E_t
+q^{-1}G_\varepsilon(-t-h;v)x^{-h}E_{h-t},\quad
r(t)=\min\{r\ge-e:r\equiv t\pmod3\}.                       \tag{4.2}
$$

This follows from the shell integral in [6, Sections9,13], with the
ordinary unit character retained. Shells below $-e-1$ vanish by
additive orthogonality. Shell $-e-1$ gives the Gauss term. Higher shells
have trivial additive character; their unit average is zero for a
quadratic twist and otherwise survives exactly in the displayed
congruence class. Summing that geometric tail gives (4.2).

The spherical scalar is $c(x)=(1-q^{-1}x^3)/(1-x^3)$.
The six Weyl terms of [6] give the unit-index spherical vector

$$
j(x,y)=\left(1+\frac{x^2y+xy^2}{q},
\frac{qx+qy+x^2y^2}{qg},0\right),\qquad g=G_0(1;1).        \tag{4.3}
$$

Both simple-root identities $C_i j=c_i j\circ s_i$ verify its
normalization directly. Put

$$
a=1/6+it,\quad b=1/6-it,\quad u=q^{-1/3},\quad
z=\eta(p)q^{-b}.
$$

The outgoing parameters after roots1,2 are $(z,u^{-1})$, and

$$
j(z,u^{-1})=(1+uz+(uz)^2)(1,q^{-1}u^{-1}G_0(2;1),0).
                                                               \tag{4.4}
$$

The first intertwiner and the outer factor (4.4) therefore supply

$$
\frac{L^{S_0}(1/2+3it,\eta)L^{S_0}(1/2-it,\eta)}
{L^{S_0}(3/2+3it,\eta)L^{S_0}(3/2-3it,\eta)}.              \tag{4.5}
$$

Indeed $1+uz+(uz)^2=(1-\eta(p)q^{-(1+3b)})/
(1-\eta(p)q^{-(b+1/3)})$. This is the degree-three Euler factor of [4]
with $3s=b+1/3$. Euler identities are first used in an absolute chamber
and then continued; no central Euler product convergence is assumed.
The denominators in (4.5) are uniformly bounded away from zero.

### 4.2. Correct numerator coordinate and deletion factors

For equal numerator $n$, rational torus translation by
$\tau_n=\operatorname{diag}(n,1,n^{-1})$ identifies its global
Whittaker character with the unit one. Locally, changing the three
unipotent coordinates gives

$$
W_1(R(\tau_n)f)=|n|_p^2\pi(\tau_n)^{-1}W_n(f).
$$

In outgoing parameters $(z,u^{-1})$, this selects coordinate
$2e\bmod3$ at $e=v_p(n)$. Combining with the archimedean Fourier-index
scaling gives the arithmetic scalar

$$
A_p(e)=(u^2/z)^e[W_n(f_{\rm out})]_{2e\bmod3}.             \tag{4.6}
$$

It is incorrect to use coordinate0 at every $e$. For completeness, in
the complex normalization $|n|_{\mathbb C}=Nn$, the incoming Jacquet
integral satisfies $J_{\lambda,n}=Nn^{a+b-2}J_{\lambda,1}(R\tau_n)$.
The short intertwiner has Fourier-index factor $Nn^{-(a+c)}$,
$c=a+b$. Multiplication of the finite $|n|_p^2\pi(\tau_n)^{-1}$ factors
with these complex powers yields exactly (4.6). Fixed unit phases are
retained and have modulus1.

At a conductor prime, the actual full-cell input is $E_0$ and the
second root after reflection is principal. Apply
$C_0(u,e)C_1(u/z,e)/(1+q^{-1})$, then (4.6). One obtains

$$
|A_p(e)|^2=\frac1{(1+q^{-1})^2}
\begin{cases}q^{-1},&e\equiv0\pmod3,\\
q^{-2/3},&e\equiv1\pmod3,\\
0,&e\equiv2\pmod3.
\end{cases}                                               \tag{4.7}
$$

At a good prime outside the conductor where both columns are deleted,
use the principal full-cell input $E_0$ and divide by the extracted
unramified factors $c(u/z)(1+uz+u^2z^2)$. Direct evaluation gives

$$
\begin{aligned}
B_p(3k)&=\frac{z(u^2+uz^2+z)}{\mathcal D},\\
B_p(3k+1)&=\frac{gu^2z(u^2z+u+z^2)}{\mathcal D},\\
B_p(3k+2)&=0,\\
\mathcal D&=(1+u^3)(u^4+u^2z+z^2)(1+uz+u^2z^2).
\end{aligned}                                             \tag{4.8}
$$

The identity $C_\varepsilon(x,e+3)=x^{-3}C_\varepsilon(x,e)$
makes these formulas periodic for all $k\ge0$, after (4.6).
Since $|z|=q^{-1/6}$ and $|g|=q^{1/2}$,

$$
B_p(3k)=1+O(q^{-1/2}),\qquad
|B_p(3k+1)|\ll q^{-1/3}.                                  \tag{4.9}
$$

All denominator ratios in (4.8) are bounded away from zero uniformly
on this line. Products over additional deletion primes cost only
$(NDNn)^\epsilon$. At primes outside $nD\kappa S_0$, the normalized
unit-numerator spherical value is1. Thus (4.7)--(4.9) treat every
variable good place in (2.1).

### 4.3. Dyadic and fixed places

The prime above2 is inert, of norm4. Its cubic cover is tame and
splits over the compact group. For a quadratic character of conductor
depth $\ell$, multiplying its unit restriction by any tame cubic
character keeps exact depth $\ell$. Primitive finite-ring Gauss
orthogonality leaves only shell $-e-\ell$, giving

$$
C_{\eta,\ell}(x,e)E_t=
q^{-\ell}G_{\eta,\ell}(-t-e-\ell;v)x^{-e-\ell}E_{e+\ell-t},
\qquad |G_{\eta,\ell}|=q^{\ell/2}.                         \tag{4.10}
$$

The source compact vector is still the unit-minor character (3.2),
now at its actual depth. Its open-cell Jacquet input remains $E_0$.
Formula (4.10), followed by the principal second root, is periodic
under $e\mapsto e+3$ after (4.6). Hence all dyadic numerator valuations
are uniformly bounded within the fixed quadratic packet. The surviving
classes may differ from (4.7), which is why the dyadic part is separated
in the counting argument. For an unramified quadratic component use
(4.8), or the spherical value when no deletion is present.

Primary numerators are units at the cubic prime. The local packet
there is fixed. Its finite-level Jacquet and positive-root intertwining
expressions are finite shell terms and geometric tails in the positive
real parts $\Re a=\Re b=1/6$, $c=1/3$. Their denominators are bounded
on this line. Thus they contribute a fixed bound, uniformly in the
unit numerator and $t$. No unbounded cubic-prime numerator valuation
is being absorbed into that constant.

At infinity the raw simple-root coefficient, with a fixed additive
character and Haar measure, is a fixed exponential power times
$\Gamma(a)/\Gamma(1-a)$. For the short word it is the product at $a,c$.
Stirling gives polynomial growth (in fact decay in this spherical
angular type). We never divide by a Whittaker function at an arbitrary
evaluation point.

### 4.4. Residue density bound

Let $\mathcal R_\eta(n;t;D)$ be the coefficient of
$(s+w-4/3)^{-1}$ in (2.1), on
$(s,w)=(2/3-it,2/3+it)$. Write $n=\pi_2^j n_0$, with
$n_0$ prime to6. The preceding calculation proves that this density
vanishes unless

$$
n_0=rv^3,\qquad r\text{ squarefree},                       \tag{4.11}
$$

and, in that case,

$$
|\mathcal R_\eta(n;t;D)|
\ll_\epsilon (KNnND)^\epsilon(1+|t|)^A
|L(1/2+3it,\eta)L(1/2-it,\eta)|
K^{-1/2}(Nr)^{-1/3}N(r,\kappa)^{1/2}.                     \tag{4.12}
$$

There is no coprimality condition between $r$ and $v$. In particular,
the class1 conductor factor in (4.12) is
$q^{-1/2}q^{-1/3}q^{1/2}=q^{-1/3}$, as required by (4.7).
The fixed normalization from Section3 is absorbed only into the
fixed implied constant. Both moving central values are displayed.

## 5. Exact finite squarefree projection

At a prime outside $nD\kappa$, the normalized polynomial coefficient
of [1] has six possible exponent pairs,

$$
(0,0),(1,0),(0,1),(2,1),(1,2),(2,2).                       \tag{5.1}
$$

The last three are collision states. Let $A_{n,\eta}(L_1,L_2;D)$
denote the centrally normalized finite dyad with all these
polynomial-$H$ coefficients and the same two column deletions as (2.1).
The following inverse is coefficientwise exact:

$$
\begin{aligned}
F_{n,\eta}(L_1,L_2;D)
={}&\sum_{\substack{c,d,e\text{ squarefree, pairwise coprime}\\
(cde,nD\kappa)=1}}
\frac{\mu(cde)\eta(cd)G(n,e)}{Nc\,Nd\,(Ne)^{3/2}}\\
&\quad\times A_{ne,\eta}\left(
\frac{L_1}{(Nc)^2Nd(Ne)^2},
\frac{L_2}{Nc(Nd)^2(Ne)^2};Dcde\right).
\end{aligned}                                             \tag{5.2}
$$

Only terms with actual nonempty daughter supports occur, so the sum
is finite. To prove it, fix a supported coefficient pair and its set
$B$ of collision primes. Select any subset of $B$ for extraction.
The states $(2,1),(1,2)$ are neutral under the Cartan twisted
multiplicativity and carry $\eta(cd)$. State $(2,2)$ shifts the
remaining numerator to $ne$ and supplies $G(n,e)$ through exact Gauss
CRT. Deleting selected primes from both remaining columns prevents
reuse. Every selected subset reproduces the original coefficient
times $(-1)^{|S|}$, so the sum is $(1-1)^{|B|}$. It keeps precisely the
squarefree states. This proof works for every natural $n$.

For a given $A$ daughter define its mixed-pole model by

$$
\begin{aligned}
\mathcal P_{n,\eta}(L_1,L_2;D)
=\frac1{2\pi}\int_{\mathbb R}
&\widehat W_1(1/6-it)\widehat W_2(1/6+it)\\
&\times L_1^{1/6-it}L_2^{1/6+it}
\mathcal R_\eta(n;t;D)\,dt .
\end{aligned}                                             \tag{5.3}
$$

The residue coordinate is fixed as $s+w-4/3$; equivalent oriented
Mellin conventions change only the same fixed factor throughout.
The integral is absolutely convergent by (4.12) and smooth Mellin
decay. Define $R_{n,\eta}$ by replacing each $A$ in the finite identity
(5.2) with (5.3), using its actual shortened profiles and deletions.
Finally define $C=F-R$.

This defines the precise subtraction in Theorem1 without a global
contour-growth claim for $C$. If a chosen contour deformation is
independently justified, (5.3) is its generic mixed-hyperplane term.
We do not claim that every other residue is absent, or that $C$ already
has a uniformly controlled shifted double-Mellin representation.

Put $Q=L_1L_2$. The line in (5.3) supplies $Q^{1/6}$. Shortening in
(5.2) changes its extraction magnitude to

$$
(Nc)^{-3/2}(Nd)^{-3/2}(Ne)^{-13/6}.                        \tag{5.4}
$$

For good $e$, the condition $(e,n\kappa)=1$ and (4.11) add the factor
$(Ne)^{-1/3}$. The total extraction mass is bounded by

$$
\sum_{c,d,e}(Nc)^{-3/2}(Nd)^{-3/2}(Ne)^{-5/2}<\infty.
                                                               \tag{5.5}
$$

A dyadic factor of squarefree $e$ has only two possibilities and a fixed
cost. It does not alter convergence. Every rescaled profile has the
same Mellin seminorm; the actual aspect ratio contributes a unit
phase on the integration line. Thus there is a common positive
integral

$$
\mathcal L(\eta)=\int_{\mathbb R}(1+|t|)^{-B}
|L(1/2+3it,\eta)L(1/2-it,\eta)|\,dt                       \tag{5.6}
$$

with $B$ sufficiently large, after paying fixed profile seminorms,
such that

$$
|R_{n,\eta}(L_1,L_2;D)|
\ll_\epsilon (KNnNDQ)^\epsilon Q^{1/6}K^{-1/2}
1_{n_0=rv^3}(Nr)^{-1/3}N(r,\kappa)^{1/2}\mathcal L(\eta).
                                                               \tag{5.7}
$$

## 6. Weighted numerator count and quadratic mean

**Lemma 2.** For squarefree good $g$ coprime to $\kappa$, $G=Ng$,

$$
\sum_{Nu\le X}1_{gu=rv^3}(Nr)^{-2/3}N(r,\kappa)
\ll_\epsilon(KGX)^\epsilon X^{1/3}G^{-2/3}.                \tag{6.1}
$$

**Proof.** Take $d=(g,r)$ and $h=g/d$. Then $h\mid v$.
Expand $N(r,\kappa)=\sum_{j\mid(r,\kappa)}\varphi(j)$.
Since $(g,\kappa)=1$, $(d,j)=1$. Ideal counting and partial summation
give, for $Y\ge NdNj$,

$$
\sum_{\substack{Nr\le Y\dj\mid r}}(Nr)^{-2/3}
\ll Y^{1/3}/(NdNj).
$$

Put $Y=GX/(Nv)^3$, enlarge the remaining coprimality conditions, and
sum $v$ divisible by $h$. The harmonic ideal sum is
$O(\log(2GX)/Nh)$. Since $dh=g$, the resulting main factor is
$(GX)^{1/3}/G=X^{1/3}G^{-2/3}$. The sums over $d\mid g$ and
$j\mid\kappa$ cost subsidiary powers, because
$\varphi(j)/Nj\le1$. This proves (6.1). $\square$

The original weight (1.3) satisfies $|w(u)|\ll\tau(u)$, up to its
fixed profile bounds. It can therefore be retained in (6.1) at a
subsidiary cost. This use of a positive majorant applies only to the
residual and full positive means, not to the desired signed complement.
For a natural dyadic factor $u=\pi_2^j u_0$, sum the shortened counts:
$\sum_{j\ge0}q^{-j/3}(1+j)^A<\infty$. A dyadic factor of $g$ has a
fixed cost. Thus the stated estimate covers all natural primary rows.

We also use the standard fourth-moment consequence of [9]:

$$
\sum_{N\kappa\asymp K}|L(1/2+it,\eta_\kappa)|^4
\ll_\epsilon K^{1+\epsilon}(1+|t|)^A.                     \tag{6.2}
$$

Here is the reduction, including nonsquarefree coefficient indices.
The approximate functional equation gives two polynomials of length
at most $K^{1/2}$ times a height power. Squaring either produces
length at most $K$ times a height power and divisor-bounded coefficients
over $\sqrt{Nn}$. Separate weights on a common conductor dyad by Mellin
inversion. Write $n=rh^2$, $r$ squarefree. The factor from $h$ is
$1/Nh$, while $\eta(h^2)$ is the bounded row mask
$1_{(h,\kappa)=1}$. For fixed $h$, enlarge the positive family after
retaining this mask and apply [9, Theorem1.1] to the squarefree $r$ sum.
Its coefficient square norm is subpower, and the bracket is
$K+O(K(1+|t|)^A/(Nh)^2)$. Hilbert triangle in $h$ costs only a
logarithm/subpower. Dual approximate-functional-equation pieces have
unit root-number row factors; bound each positive norm before combining
them. This proves (6.2), with a polynomial height cost.

Cauchy between heights $3t$ and $-t$, followed by the common integrable
weight in (5.6), yields

$$
\sum_{N\kappa\asymp K}\mathcal L(\eta_\kappa)^2
\ll_\epsilon K^{1+\epsilon}.                             \tag{6.3}
$$

Combining (5.7), (6.1) and (6.3), for any fixed two-mark daughter of
product $Q/G$ with source numerator $gu$,

$$
\sum_{\kappa,u}|w(u)||R_{gu,\eta_\kappa}(Q/G;Dg)|^2
\ll_\epsilon (KXQND)^\epsilon Q^{1/3}X^{1/3}G^{-1}.       \tag{6.4}
$$

The notation $Q/G$ in (6.4) abbreviates its two actual lengths, not
a replacement by a balanced profile. The power $G^{-1}$ is the
product of daughter shortening $G^{-1/3}$ and numerator divisibility
$G^{-2/3}$. This is the sparsity gain missed by a bound that counts
all $X$ rows with only a uniform conductor estimate.

## 7. Full projector and proof of Theorem1

First verify the exact source in (1.5). Inserting
$1_{(n,m)=1}=\sum_{g\mid n,m}\mu(g)$ into the two whole squarefree
columns, write $n=gf$, $m=gh$. Gauss CRT in the stated convention gives

$$
G(gf)\overline{\rho_{gf}(u)}
=G(g)\overline{\rho_g(u)}G(f)\overline{\rho_f(gu)}.
                                                               \tag{7.1}
$$

The extracted factors on the two sides cancel against conjugation,
leaving $1_{(g,u\kappa)=1}$. Central normalization supplies $1/G$.
Splitting $g$ between each pair of marks gives exactly (1.4), with
product lengths $Q/G$. Remaining columns are deleted at $g$; no
coprimality between the two remaining whole columns is imposed after
Möbius extraction. Thus (1.5) is the complete signed projector.
Its diagonal cancellation is not available after discarding the signs.

For the original daughter $F$, absorb $\overline{\rho_f(g)}$ as a
column phase and fix $\eta_\kappa$. The coefficient on squarefree
$f$ is divisor-bounded and centrally normalized, with square energy
bounded by subsidiary powers. The natural-row cubic bound
[10, (8.3)] gives

$$
\sum_u|w(u)||F_{gu,\eta_\kappa}(Q/G;Dg)|^2
\ll_\epsilon (KXQND)^\epsilon
\left(X+X^{1/3}Q/G+(XQ/G)^{2/3}\right).
$$

At $X\asymp Q^2$ the bracket is $O(X)$ for all nonempty daughters.
Counting the quadratic family gives

$$
\sum_{\kappa,u}|w(u)||F_{gu,\eta_\kappa}(Q/G;Dg)|^2
\ll_\epsilon (KXQND)^\epsilon KX.                         \tag{7.2}
$$

The row length here is $X$, not $GX$. The multiplier $g$ was absorbed
into the column phase. All original zero masks remain; dropping a
mask occurs only as an enlargement of this positive mean.

For each actual pair of daughters, the exact algebraic identity is

$$
F^+\overline{F^-}-C^+\overline{C^-}
=R^+\overline{F^-}+F^+\overline{R^-}-R^+\overline{R^-}.
                                                               \tag{7.3}
$$

Cauchy using (6.4) and (7.2), followed by the original $1/G$, bounds
either cross term by

$$
(KXQND)^\epsilon K^{1/2}Q^{1/6}X^{2/3}
\sum_g (Ng)^{-3/2+\epsilon}.
$$

For the last term of (7.3), (6.4) gives

$$
(KXQND)^\epsilon Q^{1/3}X^{1/3}
\sum_g (Ng)^{-2+\epsilon}.
$$

Both sums converge. The two allocation counts are bounded by
$\tau(g)^2$ and can be included by taking a smaller subsidiary
exponent. Common Mellin profile heights are integrated against one
rapidly decaying majorant. This proves (1.6) and then (1.7).
No inequality was multiplied by a retained negative Möbius weight:
(7.3) is exact before the absolute bounds. $\square$

## 8. Evidence, reproducibility and limits

The proof is analytic and algebraic. CPU calculations check the local
conventions and finite identities; they do not establish global
continuation, Whittaker uniqueness or asymptotic estimates. The supplement
contains the original proof notes, scripts, their local dependencies,
saved outputs and a hash manifest. Python3 with SymPy, mpmath and NumPy
is sufficient; no GPU is used.

The checks include both spherical simple-root functional equations,
the rank-one exceptional coefficient matrix, the all-exponent geometric
identities, the actual numerator-deleted vector, and the finite-ring
dyadic shells. The collision inverse was tested on2592 actual
Eisenstein-prime cases, including2424 zero cases. Omitting its numerator
shift fails130 cases; maximum relative floating-point discrepancy in
the correct identity is below $6.4\times10^{-15}$. The dyadic control
has96 checks at primitive quadratic depths2 and3. The earlier full
coefficient-matrix control also checks exact braid and reflection-square
identities. Saved checks were not rerun unchanged merely to package
this manuscript.

To reproduce the finite inverse or dyadic check, run respectively
`python experiments/cubic1548_squarefree_inverse.py` and
`python experiments/cubic1549_dyadic_gauss_shells.py` from the unpacked
supplement. The other scripts are listed in its README and manifest.
All original code, notes and outputs in the supplement are released
under CC0-1.0. Referenced papers retain their own licenses and are not
redistributed in the supplement.

The scope restrictions are substantive. We use the specified quadratic
packet and natural primary rows, not arbitrary additional ramified or
angular twists. The finite subtraction defines $C$ exactly but does
not prove a useful signed estimate for it, or a uniform spectral
description after contour shifting. In particular the positive bound
(7.2) still has the old $KX$ scale. One cannot subtract its restored
diagonal from that upper bound. The next research problem is the signed
correlation of the complementary expressions with the original weight
(1.3), every zero mask and the full projector intact.

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